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楼主 |
发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :8 K$ R/ g% e$ G- z- a: a' ]# N
The oscillating member is moved backwards and forwards through an angle of 90° (45° on # u/ u6 c+ \9 v' c) v
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
: }) \: [- s) p, Lmin. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the 3 S1 Z; L: }3 W# D% M" e) M$ ~& N
sample is turned through 90° about the centre line of the cord guard.
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5 W& c) \) L" z$ g4 _....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。
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翻译成中文的主要意思就是:- v/ T/ ?0 p: p4 M/ T1 ?
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on ! N$ p5 S8 K: k
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per 3 ]; `+ r M5 H0 O7 o
min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。; H+ W9 z6 o% `7 e# v
, ?0 u3 Q2 c; I! F( oAfter 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。1 z$ l3 j9 {0 M2 ^4 Y
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这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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1 q# }6 Z0 y9 o: P这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。8 X# n2 b6 c P* e* p# Z7 s$ E M0 H
4 P; j0 q9 M; o0 m/ B; q6 ]% I1 ~( Z6 v" U摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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' c0 ^, x7 k$ qA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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