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楼主 |
发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
4 T8 u0 s! F2 A$ W6 i# QThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
: J3 B4 B9 v4 f8 r: ]4 @either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per $ d1 f1 }6 G3 ?, |. ?4 l U
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the * B1 D D9 ^$ S5 `6 D3 q
sample is turned through 90° about the centre line of the cord guard. 5 P; u( G4 O! i" f
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....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。/ d. b X( J2 O& v8 c: H4 [1 F
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翻译成中文的主要意思就是:, w4 W, }2 w0 M+ J
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on
4 F* L) j. t. `& Heither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
/ k5 q2 P! n* l) F, ?6 a# Pmin. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。
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: U- C0 \ J: \0 I" ^这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。( m5 b2 ~' Q0 d( C; V) I# y4 ~
. w# B0 O( [$ p1 {0 `& L8 k9 ~这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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+ N6 L1 z6 D% m L' _摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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A flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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