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发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
3 D0 h$ d" H8 n, r% AThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
8 K3 w, n) j6 Z3 aeither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per 6 X- a2 |# A7 z: \
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
2 T; H. ]$ v$ h2 X/ V3 d- |/ h& Dsample is turned through 90° about the centre line of the cord guard. ! G3 A c1 V% s
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....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。1 ^6 V Y" t# K, n4 ~
$ J) P3 A1 Z/ ^& X翻译成中文的主要意思就是:
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on 0 \* F F5 ?2 q
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
8 T2 L0 m3 }. \8 l* M' D4 Pmin. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。# S6 m7 N# P% n* o8 @
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这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。& |/ t& o9 ?+ H' a+ ?6 G F3 m8 C1 U
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。' o5 M6 J1 {1 K) R. }* [
: K6 O2 y3 y+ I e* l' X7 {( i这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。7 @% L G {5 S7 B5 F& k
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。) |! t' w7 L O L* I7 v0 `) s) l& ]
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摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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& ~ M& H" [" w8 x; ~4 MA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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