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发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
& |$ I+ W: F% o1 u* H9 YThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
4 j2 h( u' }4 M/ Veither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
* t3 r( A+ E+ z5 |min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the ' \$ p4 Z4 ?$ t& X
sample is turned through 90° about the centre line of the cord guard.
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3 F% t7 E6 U0 h1 W; l9 V1 C翻译成中文的主要意思就是：
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* b1 i+ _; @- H7 vThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
' t- ]' x/ O0 k& n, V$ Peither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per $ a7 Z H& s m! g
min. - 摇摆装置能够在90°的范围内前后摆动（其中这个90°指的是沿垂直位置两边各45°），以每分钟60次的频率摇摆20000次。
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; N- a1 ?1 a! h* _7 p0 Z( g这句话讨论的是仪器的摆动机构要满足的特性，就是要能在90°的范围内前后摆动，如果只能在45°的范围内摆动的话，这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。9 K- L6 ~9 P' V
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后，将样品沿着电线防护套的中心线转动90°。; @& i- M* E7 U( K" g' b$ |
6 m8 f1 j% W2 j: H/ i" ?9 N: L) V# \这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已，同样没有涉及到摆动周期的解释和说明。; d( J! v" r# X$ J) @
* s ~0 p: \1 g/ B/ Q最重要的一句话应该是：A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动，无论是向后还是向前的。
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* w% d2 _: h, Q! S; [这句话虽然容易引起歧义，但是仔细考虑一下也不是很难理解。可以看出，1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动，那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。5 @4 o. u0 O7 I S, j' J* X
3 n6 v( q$ u7 M T* {摘抄UL 745-1标准中的相关章节如下，关于这个问题解释的非常清楚，供大家参考参考：- a# G1 g) l w6 H
9 D) T) Q! d1 _8 b0 SA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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发表于 2009-5-7 20:39
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