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楼主 |
发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
3 i# L: W9 i4 X$ p. EThe oscillating member is moved backwards and forwards through an angle of 90° (45° on
7 v6 V, J b# ]% D0 n) A1 f! ^" |either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per ' B/ Q; c* F1 C# {1 ~- z, j/ W
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the ! t" ?3 r! d' g3 S
sample is turned through 90° about the centre line of the cord guard. % m# w+ o/ I* ~
8 D. y8 t6 R! G5 p0 P# H....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。
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+ r; C/ r: d7 Q+ [" P( d翻译成中文的主要意思就是:
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8 i9 j0 h- S8 I( E8 U4 wThe oscillating member is moved backwards and forwards through an angle of 90° (45° on 9 D, w- [, N6 P! l! D
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per 8 n4 x/ l! ?) J
min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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$ ~$ U) D3 g! a这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。2 R2 P9 P: Q: z9 m; o
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。! Z% J* |9 D8 e# u& D8 W4 a. ~
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这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。2 b* O( x7 p9 I/ d3 o$ I5 e: i* j7 u2 g
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摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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( E* K8 K! [5 hA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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