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对于IEC60335-1其实个人觉得最重要的几个关键词: 带电部件 可触及部件 还有绝缘/器具的分类几个概念。) S; ]' p3 p# K3 Z8 N0 u
; o( s% r+ T* ?( C& U$ Y: s2 o对于任何一个产品，我们第一步要确定的是绝缘的类型：basic/supplementary/reinforced(double) insulation. 在对此判定的前面，我们必须考虑器具的类型（class 0, I, II III)。
+ \; D! w, Q1 s1 k以我们熟悉的无线水壶为例子。以(Strix connector)， 带地线.金属外壳，我们的第一印象，Class I appliance.$ x% b( d9 R( Y' O
第二步：器具是 is in overvoltage catergory II,6 w# U; y# f& o- G6 S
rated voltage 假定220-240V, so the overvoltage is 2500V.% v. o0 I w$ B
step 3: for cr (see table 16)
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) ? t3 G% ~ O1 l- _7 D7 L For basic insulation (clearance), there are two limit existed, 1.5mm for general basic insulation and 1.0mm for tubular heater
( E* q5 g5 I8 l$ W; Y W For supplementary insulation, it is same with basic insulation
, s* {0 q: {& b For reinforced insulation, the higher step limit apply from table 16, that means the value for Overvoltage 4000V applies, it is 3.0mm9 o' R% d+ n8 J; }1 Z7 K8 M3 H
+ b' q9 p" X5 n" M# d# Nstep 4: For Creepage ! j1 n( m% z0 A, g
+ a8 }( V* u D+ j- c ]2 {for basic insulation: see table 17, usaally we can determine the appliance pollution degree from concerned part 2( see -2-15 for kettle), it is pollution degree IIII. and material group IIIa/IIIb.
e$ ^( x$ T b' m3 i5 t: }there are two limit existed, 4.0mm for general basic insulation and 1.0mm for tubular heater.
4 J! V2 |% ~# Q( @8 e! X2 B: g. ASupplementary insulation is same with basic general requirement% @+ C8 r4 n& h% X( ]& f
Reinforced insulation is double the basic insulation.
0 c8 L5 [( g" a3 H, N3 }: m; `2 T( m! l, n
Please Bear in mind, above analyse is based on Class I.
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4 l; |. `+ `* o$ @1 tNext stage, i will prove to you if the appliance is sold to Japan as class 0 or class 01, what will happen. |
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发表于 2008-8-12 16:08
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