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楼主 |
发表于 2012-3-14 11:07
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herryhui 发表于 2012-3-12 18:36 
+ n2 g1 r2 v# j* [+ f+ Y+ [: }一个产品标称220-240V, 5600W, 那么产品的额定电流应该怎么算?) F+ U+ _9 e- m# X% d
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1. 230V对应下的额定电流:5600/230 ...
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rated current, i, F+ c. z# F: g0 Z0 A: O
current assigned to the appliance by the manufacturer7 s+ j' o& n+ e( O/ H% U
NOTE If no current is assigned to the appliance, the rated current is9 u/ L5 W% x" g4 X0 j1 J, D
– for heating appliances, the current calculated from the rated power input and the rated voltage;. ?' b3 c4 b9 F0 h) V
– for motor-operated appliances and combined appliances, the current measured when the appliance is
+ j3 V7 G9 Y; Q" E8 L/ |) O& usupplied at rated voltage and operated under normal operation.
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9 o& U# M% a2 r: \: j( k这个应该可以算标准支撑吧?既然正常温升可以考虑换算240V, 为什么考虑额定电流的时候就不考虑了呢?有点说不通吧? |
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