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发表于 2012-3-14 11:07
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herryhui 发表于 2012-3-12 18:36 + Z- a1 E2 R* r/ j0 l; C
一个产品标称220-240V, 5600W, 那么产品的额定电流应该怎么算?% B; U+ W2 ~' X2 G1 t- r
5 D: j& n7 l) U. ~3 M2 W/ O4 M0 D1. 230V对应下的额定电流:5600/230 ... ' D8 J8 k; J; C9 {0 j$ }& ^. D
3.1.6- E. X4 i. U i8 ?' g8 E8 k" R
rated current. R D- x/ J1 U/ b6 N
current assigned to the appliance by the manufacturer
# K/ f( F: i! f; D8 rNOTE If no current is assigned to the appliance, the rated current is
* g7 F4 f4 P' u0 ~– for heating appliances, the current calculated from the rated power input and the rated voltage;, ~1 f4 }# F1 }6 C- U2 m
– for motor-operated appliances and combined appliances, the current measured when the appliance is9 j0 v) o! M5 Y9 H' t/ J/ n
supplied at rated voltage and operated under normal operation.7 a* r5 t; J9 H( U; I
T% p( g2 m; Z% p! [2 ?1 L* n$ S这个应该可以算标准支撑吧?既然正常温升可以考虑换算240V, 为什么考虑额定电流的时候就不考虑了呢?有点说不通吧? |
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