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楼主 |
发表于 2012-3-14 11:07
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herryhui 发表于 2012-3-12 18:36 
9 {& Y. a) j: a6 q0 D3 S/ ^+ k一个产品标称220-240V, 5600W, 那么产品的额定电流应该怎么算?
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1. 230V对应下的额定电流:5600/230 ... & v0 D3 @+ x+ x" k7 l
3.1.69 V, O1 H4 h6 d r
rated current4 A- A# V% Z5 N6 L
current assigned to the appliance by the manufacturer" v: t/ d6 ^% c
NOTE If no current is assigned to the appliance, the rated current is+ C1 V3 m; `2 d; i" e) q' P2 Z
– for heating appliances, the current calculated from the rated power input and the rated voltage;* M {7 ]: A) ~% b
– for motor-operated appliances and combined appliances, the current measured when the appliance is
& {9 [6 ?7 c* B1 P" csupplied at rated voltage and operated under normal operation.6 {, g' g" O* U% j! O; f
+ T. P* I/ }2 U( B3 Z# e2 u这个应该可以算标准支撑吧?既然正常温升可以考虑换算240V, 为什么考虑额定电流的时候就不考虑了呢?有点说不通吧? |
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