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楼主 |
发表于 2012-3-14 11:07
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herryhui 发表于 2012-3-12 18:36 
) N1 k$ _7 f+ ?* A3 T. `一个产品标称220-240V, 5600W, 那么产品的额定电流应该怎么算?
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1. 230V对应下的额定电流:5600/230 ... 9 ]3 Q9 Z6 f0 [
3.1.6( ?- J5 d: [1 q, }/ C
rated current u T% i3 M1 O; c$ h: H
current assigned to the appliance by the manufacturer. p2 k" U4 s6 C& u6 p, B
NOTE If no current is assigned to the appliance, the rated current is& E9 Y# b3 `1 t1 q/ V
– for heating appliances, the current calculated from the rated power input and the rated voltage;( M% z9 u* v( f. f
– for motor-operated appliances and combined appliances, the current measured when the appliance is9 ~8 t; I7 i( s" R1 u
supplied at rated voltage and operated under normal operation.) b* m$ Q2 K& o0 q: p
5 M' V1 h0 ]8 _- M这个应该可以算标准支撑吧?既然正常温升可以考虑换算240V, 为什么考虑额定电流的时候就不考虑了呢?有点说不通吧? |
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