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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑 ) b0 K4 D7 I6 T+ D% e
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3.1.6
9 S X5 b* F( vrated current* ?" U x* ]! ~% u0 L
current assigned to the appliance by the manufacturer& v9 h( k' X% m+ y
NOTE If no current is assigned to the appliance, the rated current is" I5 p( e" g1 F' n+ R8 w
– for heating appliances, the current calculated from the rated power input and the rated voltage;9 m) ^# N) {3 f2 a: y* w, W
– for motor-operated appliances and combined appliances, the current measured when the appliance is
1 X6 O; W# C4 E# D3 w7 vsupplied at rated voltage and operated under normal operation.
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! q( _& C, o) ]- J电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.9 G% l: U* y$ ]
所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。
5 q c/ F& t( o" z9 L' P得到额定电流之后,就可以判断这个插头能不能用了。
1 W$ _& [* E; _5 |然后查25.8的表格,根据对应电流再判断线径 |
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