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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑 4 o+ x" |$ `, c( C' ~
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rated current
$ D3 m% ^8 f$ [ Xcurrent assigned to the appliance by the manufacturer( j( F; D7 c* b+ R; Z+ M9 _! }0 ~
NOTE If no current is assigned to the appliance, the rated current is% I% o8 Y0 }* Q
– for heating appliances, the current calculated from the rated power input and the rated voltage;
$ t/ f$ R* I# y% e/ Z/ R– for motor-operated appliances and combined appliances, the current measured when the appliance is
( R7 O+ |7 J; v0 i6 Qsupplied at rated voltage and operated under normal operation.$ P9 u. ]7 @1 e; W, R4 ~
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电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.
. V% Y( h* e9 n5 w) e所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。
1 b* U+ x9 D7 y: z/ K' D6 q }得到额定电流之后,就可以判断这个插头能不能用了。0 }( B$ Y! W8 _3 l/ D, J
然后查25.8的表格,根据对应电流再判断线径 |
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