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楼主 |
发表于 2012-3-14 11:07
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herryhui 发表于 2012-3-12 18:36 
& z! t o K( I8 Q一个产品标称220-240V, 5600W, 那么产品的额定电流应该怎么算?: N& \. k' R5 ~9 L+ h
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1. 230V对应下的额定电流:5600/230 ... " c: k( d3 o9 t( l( Q K I, V
3.1.6
$ }; E; w5 A: X3 Q/ Mrated current6 M3 n- T9 | }2 ~5 v
current assigned to the appliance by the manufacturer# {; R( W" H9 \+ W
NOTE If no current is assigned to the appliance, the rated current is
& k1 ?* k; D, X* ?– for heating appliances, the current calculated from the rated power input and the rated voltage;" w& L3 t' X6 ] [
– for motor-operated appliances and combined appliances, the current measured when the appliance is7 y2 R; }9 I# R7 b! a; T
supplied at rated voltage and operated under normal operation.
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9 P1 O$ U/ G3 ? b9 h; ^这个应该可以算标准支撑吧?既然正常温升可以考虑换算240V, 为什么考虑额定电流的时候就不考虑了呢?有点说不通吧? |
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