|
|

楼主 |
发表于 2012-3-14 11:07
|
显示全部楼层
herryhui 发表于 2012-3-12 18:36 6 ^( [; X; \* G0 w. |6 A9 x
一个产品标称220-240V, 5600W, 那么产品的额定电流应该怎么算?
/ D; l: Z, P/ m0 g$ D& G* X! X$ A7 ~
" R d3 ?$ t" K1. 230V对应下的额定电流:5600/230 ... 2 l9 I& Z9 p, l6 Y* P8 C! `$ b
3.1.6
/ G, w/ F( t# |5 i: C; ]' G ^( ^rated current
" A3 q6 B! Y2 c; xcurrent assigned to the appliance by the manufacturer
/ h1 c6 R: I6 a8 K9 N* d7 pNOTE If no current is assigned to the appliance, the rated current is
( S, u1 s; C. ]% j: e– for heating appliances, the current calculated from the rated power input and the rated voltage;
8 }4 r9 _6 z) R* p– for motor-operated appliances and combined appliances, the current measured when the appliance is
. j5 S1 G# [2 @; K% Qsupplied at rated voltage and operated under normal operation.0 [; e2 G6 v* o5 } Q, ]9 x
/ p* P g, d9 [# c2 w' n这个应该可以算标准支撑吧?既然正常温升可以考虑换算240V, 为什么考虑额定电流的时候就不考虑了呢?有点说不通吧? |
|