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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑
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: e: h7 U+ _: j, vrated current
) H4 B6 U, @7 b8 n$ T2 Hcurrent assigned to the appliance by the manufacturer
) k3 X/ \& S8 BNOTE If no current is assigned to the appliance, the rated current is
$ o7 D8 w' D) k– for heating appliances, the current calculated from the rated power input and the rated voltage;
0 v, _) B: L# O$ A- N D# p6 z– for motor-operated appliances and combined appliances, the current measured when the appliance is
3 j( L6 S0 ]2 E4 _# \supplied at rated voltage and operated under normal operation.
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电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.& Y( c4 z/ \$ y0 \" u; z( ~ R
所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。
& J8 n3 }( L6 ~ {7 q; R% U, S得到额定电流之后,就可以判断这个插头能不能用了。
; S: j; \+ { M* a0 ~8 a3 S然后查25.8的表格,根据对应电流再判断线径 |
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