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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑
' i, h! }% Y# k- P. {( P) k4 ^+ X) z. `2 j1 F5 X. O* ?; f: {
3.1.6
: k d) u' E: e7 Trated current
1 ^2 y4 U- Q$ Y, \7 o/ x$ X1 Dcurrent assigned to the appliance by the manufacturer5 z" ~+ I- k9 R* @, Z# I6 `
NOTE If no current is assigned to the appliance, the rated current is
) I# W1 o8 s6 i* Q– for heating appliances, the current calculated from the rated power input and the rated voltage;9 Q3 G2 v" H! G# k5 R% X* _8 F
– for motor-operated appliances and combined appliances, the current measured when the appliance is* V/ e% l7 z/ I; l F5 U) D
supplied at rated voltage and operated under normal operation.' e/ e h- F a7 H+ U$ y$ z- K
& f5 |' [2 m5 K. \0 {& w! D
/ C9 s5 R4 T4 S; I' t% b& x电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.0 D: ~% G3 ]2 z% v
所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。
5 g: ?. c' g' C+ t2 p得到额定电流之后,就可以判断这个插头能不能用了。3 N, ]0 M |) R% _1 g% K
然后查25.8的表格,根据对应电流再判断线径 |
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