|
|
本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑 1 h1 \; _0 F2 g- Y6 ?
7 f! O- g: Q2 B) N, o6 |& W# N# _3.1.6
5 E) z% P7 a( d. {rated current- f/ E' z O9 J. j. J
current assigned to the appliance by the manufacturer
1 r; y- m( G. N3 u& I7 n; ]NOTE If no current is assigned to the appliance, the rated current is
2 L, h6 I) L) a5 g– for heating appliances, the current calculated from the rated power input and the rated voltage;3 r0 O/ `' J4 z3 g1 g5 v' O4 ]( }
– for motor-operated appliances and combined appliances, the current measured when the appliance is1 j# S6 D2 h7 c8 Q# {
supplied at rated voltage and operated under normal operation.6 M% x8 _/ u# i) C0 P2 y
: y! G+ y/ K# d( p% a: e0 @& z( m! ~+ q0 u
电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.' W3 B- ^0 D! y3 Y- t
所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。" ?3 P2 j& X5 E
得到额定电流之后,就可以判断这个插头能不能用了。0 h3 X1 o& K. i" B# \7 g3 u9 z5 X
然后查25.8的表格,根据对应电流再判断线径 |
|