|
|
本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑
! D% r4 T; b% c- E' `2 s, @5 n- P, M7 X
3.1.6: E! R' R0 j+ J7 R
rated current
+ l8 L p+ h! d. W2 k, a* `current assigned to the appliance by the manufacturer
6 j _. B! `8 {NOTE If no current is assigned to the appliance, the rated current is; S6 d: y. @# \7 t6 @/ X5 Y
– for heating appliances, the current calculated from the rated power input and the rated voltage;1 l! Z8 z: f0 r
– for motor-operated appliances and combined appliances, the current measured when the appliance is
) `' m. [2 p, X! g2 }' y1 {1 ksupplied at rated voltage and operated under normal operation.
/ u$ c3 ~8 I+ Y& G$ |
; J, B4 J& s/ Z9 L. l& A
C. M/ I) q8 K电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.
! n; p L2 _1 Y5 o J5 a# `$ a/ }5 e所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。! _+ ^* q$ G- m( o0 d: G8 n! p
得到额定电流之后,就可以判断这个插头能不能用了。
1 }) s! h2 }6 Q' X {- _+ W z5 V然后查25.8的表格,根据对应电流再判断线径 |
|