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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑 / E5 ^5 n/ t; e+ ?3 {' J
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3.1.64 d( h& N1 D/ W; ~9 U* ]7 W
rated current
2 }; b+ t7 ~3 ^) _current assigned to the appliance by the manufacturer
8 X) w7 f; j9 r# I1 N- DNOTE If no current is assigned to the appliance, the rated current is
6 E. i/ f7 L2 g# b# s6 W– for heating appliances, the current calculated from the rated power input and the rated voltage;
/ y3 h- i; H$ O$ @$ q– for motor-operated appliances and combined appliances, the current measured when the appliance is9 {4 m/ \+ y y0 [# O$ [/ Y8 e7 P
supplied at rated voltage and operated under normal operation.7 S. l/ h, T/ E
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- v: {; f* ^: c3 a9 q: Q电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.1 y+ p1 | `: W% N: ?
所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。
3 X! F' Z" P5 H4 o6 L4 f8 z9 Z6 \5 h得到额定电流之后,就可以判断这个插头能不能用了。
) w- M3 s0 {* V0 D! w e. G然后查25.8的表格,根据对应电流再判断线径 |
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