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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑 % Z/ k/ w0 g. k
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$ t& y* g1 ~, _rated current7 _! c$ H0 ?7 P3 j3 W
current assigned to the appliance by the manufacturer- T5 k7 \) }- p) g5 k C! p
NOTE If no current is assigned to the appliance, the rated current is/ `: r0 C6 U3 O9 ?. R0 Z
– for heating appliances, the current calculated from the rated power input and the rated voltage;$ j* d3 C0 {7 |: ^) j
– for motor-operated appliances and combined appliances, the current measured when the appliance is
+ R9 N) v4 g/ D/ e5 b3 c4 T: Lsupplied at rated voltage and operated under normal operation.
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2 F' x3 F' b9 T# ?6 a- p+ ~- |7 u* _# _
电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.
" q5 a; E- L1 u" ], x1 P所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。
O1 k' m7 {& D8 [8 h; [* e得到额定电流之后,就可以判断这个插头能不能用了。% I9 E! ?0 _8 y# w
然后查25.8的表格,根据对应电流再判断线径 |
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