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IEC 60950-1: 2001 cl 2.6.3.4中是这样描述的:
$ Y0 g# F! B/ ^4 J sThe test current, duration of the test and test results are as follows:
, N( v5 f% {; J% h - if the current rating of the circuit under test is 16A or less, the test current is 1,5 times the current ating of the circuit under test, the current is applied for 60 s and the resistance of the protective bonding conductor, calculated from the voltage drop, shall not exceed 0,1 ohm.) A* Z& J Y) u6 H1 }+ w( \
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这里的the current rating of the circuit under test 在标准中没有解释清楚,应该理解为电源分配系统中保护装置的额定电流。楼主理解为待测设备的额定电流了。- ~ J/ Y! ?! P
7 c0 N/ o) `$ l8 B5 u在IEC 60950-1: 2005 cl 2.6.3.4已经对这一情况作了清楚的定义:- [' ^" l9 @# }- _. {6 x' l
The test current,duration of the test and test results are as follows: e" k% k% b/ J6 I4 } C
a) For equiment powered from a mains supply, if the protective current rating the circuit under test is 16A or less, the test current is 200% of the protective current rating applied for 120S.) |1 X1 t0 y' }: T
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' _* \- A3 d4 M& D$ S/ a从上面一段可以清楚地知道,其所指的是墙上的保护装置的额定电流。
7 O" v$ Q, k1 X: Y, m不过,新版中电流倍数从1,5倍扩大到2倍,时间也改为2 分钟。
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另外,需要做一点澄清的是,你的CB报告上应该是24A,因为在中国及欧洲,墙上保护装置的额定电流是16A,16 x 1,5=24A. 可能是CB报告作者把家电的25A也嫁接到IT产品上来了,虽然用24A与25A测试时很可能对测试结果影响不大。但是原则上讲是不对的。 |
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