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对于IEC60335-1其实个人觉得最重要的几个关键词: 带电部件 可触及部件 还有绝缘/器具的分类几个概念。0 E6 E) i x4 K* {, U1 d
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对于任何一个产品，我们第一步要确定的是绝缘的类型：basic/supplementary/reinforced(double) insulation. 在对此判定的前面，我们必须考虑器具的类型（class 0, I, II III)。
' U# \5 Q- {0 f9 }& c' F: u以我们熟悉的无线水壶为例子。以(Strix connector)， 带地线.金属外壳，我们的第一印象，Class I appliance.
! h% F: G& V+ Y( H* Z& z" @第二步：器具是 is in overvoltage catergory II,
2 G1 w& K0 Y6 {9 k7 `4 S3 o+ Q' L rated voltage 假定220-240V, so the overvoltage is 2500V.
, A) d3 v" T2 X" P Istep 3: for cr (see table 16)( \1 D: I, \* p5 S3 I/ P/ L( z
' w) M7 _1 W; o3 P7 V P( m For basic insulation (clearance), there are two limit existed, 1.5mm for general basic insulation and 1.0mm for tubular heater
% N" C5 l0 }' `3 ]0 @5 u7 ]$ Q4 [1 a1 y For supplementary insulation, it is same with basic insulation( e! E( T, k- |1 v3 `* G: ?6 M. |
For reinforced insulation, the higher step limit apply from table 16, that means the value for Overvoltage 4000V applies, it is 3.0mm- F8 F& |; G! B+ U6 i! |
k8 k; _) d7 s" h* H0 Dstep 4: For Creepage
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6 `0 Z( `( m7 s+ ufor basic insulation: see table 17, usaally we can determine the appliance pollution degree from concerned part 2( see -2-15 for kettle), it is pollution degree IIII. and material group IIIa/IIIb.7 K) h- {0 Z3 G
there are two limit existed, 4.0mm for general basic insulation and 1.0mm for tubular heater.+ x+ ~2 G9 W: k/ j5 B7 Y3 m
Supplementary insulation is same with basic general requirement* r3 g2 ]; @8 P, C: |2 j2 _" f
Reinforced insulation is double the basic insulation.
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! N! B: n, o* S$ XPlease Bear in mind, above analyse is based on Class I.
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Next stage, i will prove to you if the appliance is sold to Japan as class 0 or class 01, what will happen. |
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