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1) with the equipment operating under normal operating conditions, a variable resistive load is connected to the parts under consideration and adjusted to obtain a level of 240 VA. Further adjustment is made, if necessary, to maintain 240 VA for a period of 60 s. If the voltage is 2 V or more, the output power is at a HAZARDOUS ENERGY LEVEL,unless an overcurrent protective device opens during the above test, or for any other reason the power cannot be maintained at 240 VA for 60 s;1 k4 J# e8 A, O+ V v4 L3 C
2) the stored energy in a capacitor is at a HAZARDOUS ENERGY LEVEL if the voltage, U, is 2 V
) A7 W5 L- H* ror more, and the stored energy, E, calculated from the following equation, exceeds 20 J
* U: r. _/ n+ w& o M. D如60950，先判定是否属于HAZARDOUS ENERGY LEVEL，然后再判定可接触性
* |+ v- R8 J8 C" V( T" O9 T: K0 e8 s1 z$ }
a) A risk of injury due to an energy hazard exists if it is likely that two or more bare parts
4 L) {9 a8 z& E* m; o! s* @(one of which may be earthed) between which a HAZARDOUS ENERGY LEVEL exists, will be
- M4 v& h& ^( K3 C4 e( Y# }2 g3 bbridged by a metallic object.: B1 n; U! @' s) L3 e3 ~! c: T
b) The likelihood of bridging the parts under consideration is determined by means of the test+ o- N8 T% t% n! _7 e5 M
finger, figure 2A (see 2.1.1.1), in a straight position. It shall not be possible to bridge the
4 m- A, f% c# q J' mparts with this test finger, applied without appreciable force.
" v6 s, v; s/ j3 V. L. k你所说的只是一种情况，没有保护装置或其他原因导致提前当机， ENERGY LEVEL超过240VA，* b9 r. Q$ V I, I5 D9 A
持续时间达到60s，电压大于2v,才能称作HAZARDOUS ENERGY LEVEL, t5 V. k% F0 ]+ Z
然后根据（a）（b）判断可接触性，才能说Energy hazards是fail or pass |
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发表于 2009-11-2 13:40
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发表于 2009-11-2 19:18
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