UL 8750 故障测试中的8.7.2 中Exception No1对于不超过50W的电路可以豁免故障测试

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UL 8750 故障测试中的8.7.2 中Exception No1对于不超过50W的电路可以豁免故障测试。三个问题
1.是不是说只要经过8.8 Circuit power limit measurement test的评估确定这个电路是小于50W的就可以豁免故障测试
6 E3 a9 j0 u3 K5 j* ?6 n! \& I2.这个50W的电路不论输出是高压还是低压都可以豁免吗？还是说低压输入的电路？
3.目前有一个带电池的灯具，电池输出为12V，灯具只有10W，里面有电路，这个电路需要做故障测试吗？

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8.7.2 Component failure test
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8.7.2.1 A unit having components such as resistors, semiconductor devices, capacitors, and the like shall
; n# n- s# g* [2 `not exhibit a risk of fire or electric shock when a simulated short circuit or open circuit is imposed. In
& g! ~; i: m& W& f2 qpreparation for component failure tests, the equipment, circuit diagrams, and component specifications
are examined to determine those fault conditions that might reasonably be expected to occur. Examples
include: short-circuits and open circuits of semiconductor devices and capacitors, faults causing open
circuits of resistors and internal faults in integrated circuits.

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) i8 i! Y$ j0 `Exception No. 1: Circuits in which maximum power levels have been determined to not exceed 50 W need
not be evaluated for component failure.

! M; u( ]5 N6 D8 SException No. 2: Devices supplied by a source operating within the limits for risk of fire and electric shock
need not be subject to this test.

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8.8 Circuit power limit measurement test
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) o9 Y3 F( I. ?$ Z( l6 P. S8.8.1 This test shall be used to determine if the power available to a circuit under any loading condition,
including short circuit, measured after one minute of operation exceeds a defined limit. For the purposes
3 ~/ P$ k' a) J5 N0 v6 Uof this test, the limit (for example, 15W or 50W) is referred to as PLIMIT. This test is applied to a circuit
1 f' N9 _: \3 r6 A: o6 V6 E(under evaluation) to determine if it has a power draw of PLIMIT or less.
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