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在60335-2-29里面的figure.101网络,电容的计算0 h7 S0 B" U. \* [+ |
Capacitor having a capacitance, in farads, given by: 12.5*lr/p*f*Ur
! ~( H; S- G$ H# i9 f* Hwhere lr = rated d.c. output current, in amperes; 3 b8 a- N2 S1 c
p = 1, for half-wave rectification and 2, for full-wave rectification;
* n' T9 [7 ]& X6 z. Q, C8 h% `. [ f = supply frequency, in hertz; ( U3 o6 a% i; z2 n( D
Ur = rated d.c. output voltage, in volts.
7 H7 ]5 d' s4 A9 i6 M% S# \) N1 Q+ u
, U) \4 k& _& y% x这里的半波整流和全波整流指的是哪里呢?" i) E$ C' S& \, M
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