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在60335-2-29里面的figure.101网络,电容的计算% C6 m' v' M! |9 e0 e
Capacitor having a capacitance, in farads, given by: 12.5*lr/p*f*Ur9 b# O w. X4 e' E4 R4 _7 r8 d
where lr = rated d.c. output current, in amperes;
! Q6 N4 l6 n7 U# c! P4 [9 fp = 1, for half-wave rectification and 2, for full-wave rectification;
! r# G# X" p2 N+ q* F f = supply frequency, in hertz; & e2 [* W9 t3 [: S/ c& r; c6 ]* i
Ur = rated d.c. output voltage, in volts.
u2 E/ A4 p/ u4 ]# M) E7 ^
x% X* t9 C- w6 f/ q {" u, H# V& L; T8 M( n: S/ {8 e
这里的半波整流和全波整流指的是哪里呢?/ W- v' T1 O; S9 R
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