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求解：标准中有说电量的计算是通过2000 Ω电阻，测出电压/时间曲线，求出电路二端的放电电量。好久没用高数了，对于此电压/时间曲线，如何计算？积分公式是怎样的？
. B$ Q' \7 C' S- k2 a9 G' z, }% W t9 \# |* u! P6 S: |
If protective impedance is used, the current between the part and the supply source shall# a$ l8 S, S3 A/ O- G/ i- X# V
not exceed 2 mA for d.c., its peak value shall not exceed 0,7 mA for a.c. and" {1 l; U' _2 g& a" V# W1 O
– for voltages having a peak value over 42,4 V up to and including 450 V, the capacitance
6 V& u% P" D% E! E- X# C! ?/ bshall not exceed 0,1 μF;
: d" r( F/ D6 @: P– for voltages having a peak value over 450 V up to and including 15 kV, the discharge shall
" C* c1 |0 y! u, e6 l. k5 @not exceed 45 μC;
: ~: N% b( f0 c M* u; k– for voltages having a peak value over 15 kV, the energy in the discharge shall not exceed6 W7 b" R) I2 X: r
350 mJ.
1 L B1 L8 b8 @2 H: R: i$ NCompliance is checked by measurement, the appliance being supplied at rated voltage.( ?1 e8 h* n8 `( ]$ v- t4 W. H
Voltages and currents are measured between the relevant parts and each pole of the supply
# A f) S6 Y: D) I2 ~source. Discharges are measured immediately after the interruption of the supply. The
- o b6 ?7 ^3 z5 Fquantity of electricity and energy in the discharge is measured using a resistor having a
! J: ^5 E) x" S1 p" F) Cnominal non-inductive resistance of 2 000 Ω .
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发表于 2016-8-15 16:43
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