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我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.
9 Y4 ~$ _' o: S; s问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:
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第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.13 @ X3 a, W7 R; m: `: @1 P$ v
20.101.1 Lawn trimmers1 N d. [" c/ W b. }& _" K9 i! `
Lawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown& z' o8 T. _- E$ A
in Figure 101.4 x' r* H d+ s7 y! m' f
The radius X of the guard shall not be smaller than the major swept radius of the cutting; f- @( Q1 z4 f/ ~) z: ?$ z
head and the guard shall extend beyond the plane of the cutting element by at least 3 mm( `2 W2 T" W& B3 O. N
for walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall. J6 b$ i- a2 ^3 R7 l! s! ~: i+ ?
extend at least 45° from the axis of the handle on the side where the cutting element is
. _" V e4 C2 G$ T2 {. Lmoving away from the operator and at least 90° from the axis of the handle on the side where# j( y! `) Y" a' x
the cutting element is moving towards the operator. The vertices of these angles lie on the
' `: l* v# Y4 r6 t1 N0 ^- daxis of the cutting head spindle.
+ e$ y# {+ E1 o, U8 {0 Z. F7 J& X& hIf the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)
: E: A4 Y# d2 ~shall be marked on the lawn trimmer.
3 Z3 T- O2 k+ O6 `7 K8 X0 UCompliance is checked by inspection and measurement.$ h" F1 @0 @. T
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第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103
. I# z7 b* H: O9 `$ f) S0 F& ?" a" u22.103 A cutting element shall have a kinetic energy of not more than 10 J.
5 F: {, e4 S; H0 C. m J5 a4 QCompliance is checked by inspection, measurement and test. Polyamide cutting elements
% L7 u7 t- z0 O8 ^3 zare stored for at least seven days in a humidity cabinet under the same conditions as those
% A- r' N m: [9 u- k) xrequired for the test of 15.3 before carrying out the test and measurement.
8 ? V: d1 G4 f/ f# ]$ wFor the purposes of this standard, the kinetic energy shall be determined by means of the3 k! k& v" o8 Q2 g, ~3 h, h
following formula:
: z1 A! ?! G, I3 A3 m% ?# ukinetic energy = ½ mv2 (J)
- I! J2 J% _3 V1 x7 Gwhere, W3 q0 b# @) f# S% z- {$ M
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);4 b. R2 }! m, R- j- W9 H
v is the maximum attainable velocity of point Z which is half-way along the length L of the
4 r4 Q+ L! V- b5 O- P( J, ~0 Ocutting element, in metres per second.; n4 Z1 N; a( o& S) G, |
Therefore: v = 0,1047 n ( r– (L/2))9 D R+ B) Q( U
where% l9 @% p% _: Y6 Q) J" D
n is the maximum rotational speed with a full length of line or a new cutter fitted, in2 O4 `. w: s2 i F" d! ]
revolutions per minute;
1 A9 W R& P5 ~$ l$ gr is the distance from the axis of rotation of the cutting head to the outer tip of the cutting& t) [% |$ e" s& D! V, G
means, in metres;
+ v* p/ Q" Q0 w/ R7 j+ |L is the measured length of the cutting element, in metres.
: |7 ^" r2 C% y: E& z3 D. I* k/ u
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