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' h) _4 Q/ m/ f( J; _6 ? |Standard:
) A3 \, b7 `; N. d: m- Q4 u5 c* ]IEC60065 6ed.( X. I3 @* r# w4 Y' @) \& D
Sub clause:
+ y0 C" E# r) G& k6 e( f' o3 w13.2* T4 p7 `# s- a& v- B5 s- o3 R
Sheet No." {* H0 F5 v+ D- q+ q# L% [7 o
525! {7 `% B0 P) P- c5 [
Subject9 V+ m( k& W& I2 H% ?* v9 Z+ q ~/ X4 c
Applied force for internal parts+ x" l: ] k" i0 p' |, Z$ Z
Key words:5 z, K! [; K1 T/ R, L: R
force for internal parts. ?( R1 }/ ^7 X% e9 f
Decision taken at the8 {2 l8 b& a( ~2 M. ]+ v( Y
40th meeting 2003
# Q0 H& @ A) ]/ W. d4 pQuestion:. Y3 D- c, E) V [
In clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied
7 p% j$ g5 W; d0 X; h1 \, v; [simultaneously while taking measurement of clearance. However, it is not specified that forces are& `9 o. w: a2 ?7 j# M# H
applied to internal parts while taking measurements between two internal parts, ex. primary circuit" S- u; Q h3 s- T
component and secondary circuit component.
$ @7 Z& L3 y9 |9 \ \& R) |Which is the appropriate method to measure clearance between two internal parts ?
9 n" w0 k( g% a( Ca) 2N forces are applied to the both parts simultaneously.
- j- K4 J5 X9 e2 h& F7 `, f/ fb) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.
- m9 Y! i5 t/ ^0 j8 c/ J$ _1 Kc) Other opinion5 N" ]$ T) ^5 J2 A0 f p
Decision:
: C2 E, ?, E. w) _First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
* [3 x) A# R! v2 U8 Npart." w: e/ r; {# c
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