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|  DSH 387
) _& N& W$ [; n, t- E9 S" b# r; N) F4 E6 P/ F* m
| Hazardous Voltage
- O$ n9 `: a5 c G$ z | 1.2.8.3 / 12.8.4% Q' ~+ z# K0 U! j; r8 W6 m, o
| 60950(ed.2) & 60950(ed.3)0 x) l1 ?! r% y8 U6 M3 K
|
, i5 [6 o! \0 {1 v0 g+ M* T
Standard:7 b7 ^% p9 l. ]6 i( a+ Q/ a
IEC60950, 2nd (3rd) Edition
+ n6 G4 S$ ~, }8 V1 K, y( eSub clause:
4 j" X! H" H! g$ k2 y1.2.8.3(1.2.8.4)' e% l8 @4 g% x8 \! P7 d# b: `( y
Sheet n. 387
+ V H. X1 K! X' OPage 1 (1)" \! w: G0 z/ u, s' S
Subject:; U) h; E1 }: B4 s
Hazardous Voltage# _8 `- _: ^/ l9 y
Key words:
/ [8 m4 D0 }( j8 F, W& m-Hazardous Voltage- U; K7 d3 l. O6 N
Decision confirmed" j+ K& ?4 P4 Q8 V( n9 Y& @5 }
at CTL 38th meeting
. c+ R4 f: q8 E. ]3 R# UQuestion:
. p1 T3 t! n! n* ^0 `6 c6 hWhich of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance
; w+ O- O4 M# S+ m' ycriteria, in order to determine whether the voltage shown in the graph is hazardous or not?) g' k" D3 Z% Z7 J& ^9 P' f' E; b, k0 V
Condition: The circuit that generates this voltage is not a limited current circuit.
) {$ g; g0 O1 }5 C3 p* BDecision:
' z1 i. S, R8 P; fThis voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3. R6 k( q( r' y2 o
( R+ C; s9 S) } T, F. k3 v& Z; |% N( J
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发表于 2012-11-6 17:16
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