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% o! g3 _# J9 e DSH 5340 w0 U6 y" m% l7 }$ r: B! [& Z
| Figure 21, presence of resistor of 45 kO
7 p i$ w* u& J% Q* _, ?0 f | 19
' }& N1 C3 [4 J4 S+ V | 60601-1(ed.2);am1;am28 C6 h! f1 H0 V1 g. N
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Standard(s)- (year and edition):
; Z$ @8 D6 l& N' b7 Q |IEC 60601-1:1988 Ed.2& D b" H; M# a$ L R
Am1+Am2
3 J/ R0 R' k: C U8 uSub clause(s):1 H( A8 V" X9 t: ]+ \$ B
19) {# O- l, U5 v7 u$ y; `
Sheet n°: 534: c( F( ?/ u9 ?$ [' z" Z& _( y% @ u
Subject:
8 g& s% s1 V7 x# Z" m, V8 LFigure 21, presence of resistor
K' v- k" X% ^7 Y! aof 45 kO' J: y# `& |( ~
Key words: Decision taken at the 40th
. T% E6 w6 a9 Z& vmeeting 2003
7 ^( F* U& h2 {+ ?7 ?" DQuestion:
# {' r a/ e+ y! TShould the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?" z3 g( w; {2 A; z" y, k* X
Decision:
# I, c$ a, {! |; `For the 1st edition, use the method of 2nd edition (use any resistance).
( i" h+ z) l- u2 LFor 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.
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发表于 2012-9-19 15:49
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