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/ s4 c1 D) e3 u& z) N4 I DSH 534
* Q) `/ ~. i0 [; `8 O; J( e | Figure 21, presence of resistor of 45 kO
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. x+ d6 @' i" @9 s* D | 60601-1(ed.2);am1;am2 p2 R/ c8 s% X5 H- W( D1 ^0 A
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9 w% `( m; f7 m6 M& W' xStandard(s)- (year and edition):* C! ~ M- V9 h! K( N' l6 e5 H1 f
IEC 60601-1:1988 Ed.21 T/ f1 _1 [+ b. I
Am1+Am2' b9 p* I4 K# }, T, W
Sub clause(s):
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Sheet n°: 534
* g | L* j! F$ x: JSubject:
( r& H {8 }; r4 V5 I: R2 C) g* ^+ MFigure 21, presence of resistor
3 h) e Z% M9 p5 ` @' I+ }0 xof 45 kO
! p0 X% M: n9 V6 E2 t4 XKey words: Decision taken at the 40th
; _5 P8 t" _# ^+ j xmeeting 2003
- q2 P/ p1 J: C0 _, R# k6 \# hQuestion:+ j$ b0 O/ h b; K" }, n& E6 a* Y
Should the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?
8 S% A. l' D# T; c% l6 kDecision:3 H4 J- L9 j6 S0 i# n
For the 1st edition, use the method of 2nd edition (use any resistance).
5 o7 f+ c% o4 c, PFor 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.
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发表于 2012-9-19 15:49
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