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| Figure 21, presence of resistor of 45 kO ] R7 }$ j' v
| 193 I3 z# q) p2 Q5 f. q3 B% o+ B) P. x
| 60601-1(ed.2);am1;am2
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; y* o$ ~) z& i- r, lStandard(s)- (year and edition):
' a, J u: U! e) i% j) GIEC 60601-1:1988 Ed.22 e- U* ^- c/ m5 C' H+ @
Am1+Am2, S9 d" Y' |" l4 D1 g* [
Sub clause(s):4 O% _& `4 H- k
19$ H( y$ @1 l. U# d4 D8 z
Sheet n°: 534
8 r4 r4 K5 Y* M* m6 v% F- MSubject:
+ d4 E; L% t+ x6 p CFigure 21, presence of resistor. q7 C5 S6 r) Y5 Y
of 45 kO
- D& C# h7 Q; }. \+ Q& W WKey words: Decision taken at the 40th# r3 M8 Y9 z4 b, p7 d
meeting 20031 F' W1 b) V( G1 m; Y
Question:
: p: Z6 X/ _: P- F, U" M) o* ?# FShould the 45 kO resistor be used since the current is limited to 5 mA and the limit is 5 mA?
4 g* w- w" B" n" s& [6 aDecision:1 q7 c" W9 M8 u- ~6 h4 M$ s% J
For the 1st edition, use the method of 2nd edition (use any resistance).
( {, {7 y/ @/ x; e% _5 uFor 2nd edition, instead of using any resistance, you may also use alteration of the voltage or fuses.
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发表于 2012-9-19 15:49
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