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本帖最后由 aaainmaya 于 2012-9-14 15:01 编辑
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: X) K7 b! c% B nrated current
1 [3 n$ D! @' x+ z- G& V4 X( bcurrent assigned to the appliance by the manufacturer
/ j& m6 R8 n8 d, B2 ?& N5 qNOTE If no current is assigned to the appliance, the rated current is$ R4 o: a( U+ J; K. g
– for heating appliances, the current calculated from the rated power input and the rated voltage;
+ o9 C2 x L& H1 t- O% m3 V" F4 O; v– for motor-operated appliances and combined appliances, the current measured when the appliance is
+ r& e' s( u7 j: a; ^supplied at rated voltage and operated under normal operation.
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5 G" ^; o0 m3 i+ h( }电动类的额定电流是the appliance is supplied at rated voltage and operated under normal operation.9 B# V( r2 S1 e; f; V% \& t
所以你需要测量“正常榨汁时功率大约300-600W”时候的电流,电流是持续变化的话,需要取积分。1 e/ S7 [1 J! r1 U2 t% e
得到额定电流之后,就可以判断这个插头能不能用了。. w# u8 o' R. E; U6 g
然后查25.8的表格,根据对应电流再判断线径 |
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