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3.1.6
( Z3 r# n. p: w0 U Krated current A: u0 G. P1 g, W( v3 P
current assigned to the appliance by the manufacturer- V' @; A) o4 \" ^# \* v
NOTE If no current is assigned to the appliance, the rated current is
% t7 K0 t, I* P0 Q– for heating appliances, the current calculated from the rated power input and the rated voltage;
5 f1 ]6 W( F+ J% u! t; E– for motor-operated appliances and combined appliances, the current measured when the appliance is supplied at rated voltage and operated under normal operation.0 |( K) H* N1 F3 A
9 ]8 a& L/ G" y# l n7 A( b/ C
10.2: o+ o: P: |: ~" I
If an appliance is marked with rated current, the current at normal operating
; l: v' b$ E2 t& _5 R" x" m/ w, Ktemperature shall not deviate from the rated current by more than the deviation shown in& W, t9 l; _9 K$ P3 W
table 2.* K3 `0 Z# {9 M! R& j
- Z2 X& E# X- A' |6 U8 \9 @25.8
) M8 J6 a+ }2 }1 ~$ c$ OConductors of supply cords shall have a nominal cross-sectional area not less than$ S* Y. h) r; y8 }4 U' e7 y6 M
that shown in table 11.. z! `1 X# O8 {) I) m
H9 L# q. e( Y' r3 v8 b+ _& S+ o# t; B N, ?4 H9 t
根据标准25.8中表格11描述导体的线径由额定电流决定;而额定电流又是由厂家定义(3.1.6);并且额定电流按照10.2规定,可以有偏差。3 p1 ?% w# S$ I- x6 T S
; m% D0 Q, }# {" H3 e( p( C6 @问题:一个电动器具,厂家定义额定电压:230 V ~/50 Hz 额定电流:10A, 但实际测试10.2中电流为5A,按照10.2的规定电动器具额定电流大于1.5A只有正偏差的要求,则厂家这样定义符合要求。! O0 ]6 j/ O4 `' c- u6 [: I8 P
在这种情况下,我们是按照实际测试的电流来决定电源线的线径或按厂家定义的额定电流来决定电源线的线径?如上面例子是至少0.75mm²的线径符合要求,还是按照厂家定义的额定电流至少要1.0mm²才符合要求?
( A1 W( P# C. t! N; u* e1 f- K3 x! \& I, D; P
另外,请问表格11规定的根据载流量来选择线径有引用哪一份标准吗? |
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