电动打草机线头飞溅伤脚问题

terrywong

广东安规检测
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IEC60335试验指甲

我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.
问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:
. g% r" ?  ?2 d/ g) l- `
2 f7 ^, I6 i% d7 B第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1
20.101.1 Lawn trimmers
Lawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown
. |# G$ D5 M) D+ o2 bin Figure 101.
The radius X of the guard shall not be smaller than the major swept radius of the cutting
head and the guard shall extend beyond the plane of the cutting element by at least 3 mm
' ^/ h9 p1 E' `: i2 _: zfor walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall
extend at least 45° from the axis of the handle on the side where the cutting element is
moving away from the operator and at least 90° from the axis of the handle on the side where
the cutting element is moving towards the operator. The vertices of these angles lie on the
3 K* _( R' J6 ^0 d! {axis of the cutting head spindle.
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)
7 @* k, U  p( A5 I& Lshall be marked on the lawn trimmer.
# |+ z3 r' A6 D- v% E2 nCompliance is checked by inspection and measurement.

6 s1 _0 r& }# p' ~, r! Y! M第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103
3 [( ~  f7 r$ {22.103 A cutting element shall have a kinetic energy of not more than 10 J.
' h: ?4 Y- O' a" vCompliance is checked by inspection, measurement and test. Polyamide cutting elements
. [. x% y+ s# {0 w8 P" l" q: k6 ]- Lare stored for at least seven days in a humidity cabinet under the same conditions as those
required for the test of 15.3 before carrying out the test and measurement.
For the purposes of this standard, the kinetic energy shall be determined by means of the
1 L4 j6 Q, D" `, T1 Ffollowing formula:
kinetic energy = ½ mv2 (J)
where
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);
# `# X5 N- X" |/ ]v is the maximum attainable velocity of point Z which is half-way along the length L of the
cutting element, in metres per second.
Therefore: v = 0,1047 n ( r– (L/2))
where
9 ^# N2 w' N9 B9 j- bn is the maximum rotational speed with a full length of line or a new cutter fitted, in
" ^  ]# q3 E+ E/ Q7 prevolutions per minute;
r is the distance from the axis of rotation of the cutting head to the outer tip of the cutting
means, in metres;
4 Q. B6 {5 Y& F5 L- \+ O7 ML is the measured length of the cutting element, in metres.
3 \) V/ {) ^' Y+ n* h
6 |  ?5 Y5 B# _- r3 o
2 A* R$ E7 w4 F) l+ |2 b

terrywong

CE-LVD/MD 测试都通过, 也拿到了某机构的GS证书.  但还是有投诉, 证书的严肃性我们暂且不谈, 只想单纯谈论问题, 和解决问题的方法. 不知道我的上述分析对不对, 如果对, 可否告知解决方案, 请各位不吝指教. 谢谢啦