大家有没有发现Toaster标志里的这个矛盾啊？求解～～～～

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搞过toaster的是否遇到过这两个测试的矛盾点？
  |) M( y* c( ^$ |+ P4 n  |8 G0 l
: n' Y& }$ \- R: F60335-2-9里cl.19.102 规定：

# v5 v  a; |0 ?. l% D1 I19.102 Toasters, loaded with the bread specified for normal operation, are operated at
* h% f% K* _! i$ V/ f. W  y6 M9 Nrated power input. The ejector mechanism is prevented from releasing and the supply is
maintained to the toaster after the timer has completed its maximum cycle.
3 m# O' Y1 L- `+ e' S- w/ [" _
+ Q6 a) T2 f9 h
然后到了cl.22.113里又说：

. t  ^- ?3 Z8 a22.113 Toasters having an ejector mechanism shall be constructed so that they switch off
4 e; W% p/ C3 O6 @! Q/ ^7 @automatically after the normal toasting time even if the ejector mechanism is blocked.
6 P/ H1 N- V9 A; z2 QCompliance is checked by the following test.
The toaster is supplied at rated voltage and the ejector mechanism is prevented from
releasing. On the completion of the normal toasting time, heating elements shall be
& d& B- O7 _4 T0 V2 u- ~) ^8 `automatically disconnected from the supply by at least an all-pole disconnection, microdisconnection.
However, a single pole, micro-disconnection is allowed, provided heating
/ U1 b6 v) d/ `% I$ Delements are not accessible to the test probe 12 of IEC 61032.

0 M' L+ r% I' a4 a
0 Q* c1 \4 Z4 `4 [8 p什么样的机制能使得ejector mechanism失效后，全级断开开关能动作啊？
6 o, K1 m2 w1 P# r$ x3 a

6 U  `# W* Q5 M* X. y

xuanzhengbo

个人理解：
7 a0 L0 T3 e( u9 I$ X( m19.102应该是针对面包没放置好，卡住了内部的弹起装置，~
# @: O& F2 a3 d$ p5 c/ n- w/ ~5 h22.113应该是针对使用者在使用过程中不小心压住了外部的level（比如不小心放了本书啊，重物之类的吧）
$ v6 p8 q7 J9 v# @7 j
Australia的最新的标准就是说如果toaster的外部level的设计不会被无意压住，比如level的把手低于器具模具，则22.113不适用吧~~~
- x  u1 n; j" N8 K$ N( q8 B3 m! r
" B, C& e' [) s1 V7 w4 t要满足22.113的全集断开。。。。等等要求是可以做到的~~从机械上也可以，从电路上也可以。

yuanmingyu

caballo3157 发表于 2013-2-7 11:21
2006版：
19.102 Toasters, loaded with the bread specified for normal operation, are operated at
$ }' R0 O( u4 M9 O% tra ...

十分感谢你的解答。按照我之前的理解，19.102测试是放了面包的，按照2006版，其实就是一直加热，也就是从里边堵住弹起机构，最后面包应该会起火的，这时此条标准可能是考查面包机靠近面包的外壳或塑料件的阻燃性。

8 d4 a/ y/ a/ P) C: F而2008版heating element改成了toaster,理解为可以在按键处堵住弹起机构了，应该是为了迎合22.113吧？你觉得22.113是怎么实现的呢？是不是不需要特殊的结构，只要弹簧弹力足够大，稍稍弹起，有一点空隙就可以满足，因为只要求至少全极微断开。不知道我理解的对不对，如果能提供图片就更感激了。

2 N: o2 B5 J5 U( N" g# `+ g9 T另外19.102是额定功率下工作，22.113是额定电压，我没搞懂为什么会有这个区别。

caballo3157

2006版：
19.102 Toasters, loaded with the bread specified for normal operation, are operated at
0 A* z$ q! c; b' i' Urated power input. The ejector mechanism is prevented from releasing and the supply is
: b2 d7 f/ W2 X% smaintained to the heating elements after the timer has completed its cycle. The test is
terminated after any fire has extinguished, after which any residual bread is removed from the
toaster.
( G9 Y' W8 n, y* z* E+ a2008版
19.102 Toasters, loaded with the bread specified for normal operation, are operated at
rated power input. The ejector mechanism is prevented from releasing and the supply is
- _4 a% o* M9 K* R: C! xmaintained to the toaster after the timer has completed its maximum cycle.

caballo3157

22.113是标准2008版增加的内容；之前2006版无此条，且19.102的描述两者也有差异。仔细对比两个版本19.102的叙述应该对理解现在19.102和22.113有所帮助吧。
% _5 |% C8 T& g7 c* W2 V- }4 t, |两者并不矛盾，且相互有关联，不过侧重有点不同。（注意：一是非正常，一是结构的要求）

yuanmingyu

求指点，山炮的高手现身啊

yuanmingyu

yuanmingyu

各位版主，高手就没有能回答这个问题的，失望了。

yuanmingyu

:o:o:o

yuanmingyu

没人能帮忙解释一下么？那我就一直顶，等高手到来