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灯管用第二种方法测试电压24.2V,算出来有48.4mA。而我在实验室用228 表测试只有2.5mA. 不知原因出在哪里?现在负责的工程师坚持第二种方法的测试结果,因为标准根本没提到可以用228表测试。
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: a& u% m+ l3 d: X/ T第一种方法:Readings were taken directly in MIU using a suitable leakage current meter (i.e.: Simpson 228 set to "let go", etc.).
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第二种方法:Readings were taken in millivolts using a suitable voltmeter connected across the test circuit defined in UL935, Figure 24.2. These readings were then converted to MIU by dividing them by 500.
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