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Standard:8 g* I5 ^* g# Q0 T( p! F
IEC60950, 2nd (3rd) Edition
2 B5 J& @& c, K8 l2 `2 i- h; iSub clause:1 n' W7 Z0 |) b6 v& m
1.2.8.3(1.2.8.4)' ?2 x) r1 ?6 [% C2 S% d# k
Sheet n. 387
% T4 p% J# W) M6 n) Z4 M8 hPage 1 (1)0 M6 a; b# D6 ^- e8 A
Subject:
+ N* I$ g. d7 N0 I) k oHazardous Voltage
3 I: j& b2 M4 _- X. h; Y6 ~Key words:
. [1 m4 H8 _/ N$ ~' U/ l6 ]* b-Hazardous Voltage
* j* S, D* G uDecision confirmed+ Z( @& B! `0 i% s: n% X
at CTL 38th meeting( v, n. V% m! H9 e
Question:: i( t0 ^1 x0 e# k! m: g5 R; D. p
Which of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance, C0 `1 ^& j* f# ?) {$ O7 [ G. `! a
criteria, in order to determine whether the voltage shown in the graph is hazardous or not?
% H6 G. ^: Z. v8 z, E; ?+ nCondition: The circuit that generates this voltage is not a limited current circuit.' A' ?6 S( G P- |- ?
Decision:5 q8 Z0 t3 B: C4 ?* I& x- Y
This voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.3" H3 @7 A$ n( k$ Z# {
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发表于 2012-11-6 17:16
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