DSH 525 Applied force for internal parts

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DSH 525 / Y+ \& c' W) y/ A8 ~

Applied force for internal parts

13.2

60065(ed.6)   K8 q3 H; M" \1 U

( Q# X( ?6 b4 T3 jStandard:
' K% f; B9 q7 V. Q1 |' {, X: kIEC60065 6ed.
+ q1 d' t. ~/ d  {1 CSub clause:
9 f# q# l+ U. `0 I13.2
Sheet No.
& w% B1 X: q) V$ A) Z525
4 b0 ~8 a4 o% l' r% X! iSubject
- D" y. ?5 N% a- `5 H# |) cApplied force for internal parts
Key words:
force for internal parts
Decision taken at the
* Y( ]4 e7 {& o3 A4 ~4 x40th meeting 2003
Question:
( M& l8 C; ^1 zIn clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied
& T' t9 G# o2 ^5 k7 G+ Esimultaneously while taking measurement of clearance. However, it is not specified that forces are
; K8 T3 x8 d/ I- S' Lapplied to internal parts while taking measurements between two internal parts, ex. primary circuit
5 L1 x! ^3 C+ s, Z1 Y& k6 [$ kcomponent and secondary circuit component.
* r) W' t6 b0 S5 w+ d1 p5 ~Which is the appropriate method to measure clearance between two internal parts ?
" [0 V: v) U/ Sa) 2N forces are applied to the both parts simultaneously.
7 j& c) ~- J6 ~# j& Bb) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.
+ G# u' B+ e% k' C* [3 rc) Other opinion
Decision:
First, a 2N force is applied to one part and removed. Then a 2N force is applied to the other
0 a$ f! V+ G) F! t, mpart.
8 C+ e/ Z0 }3 r" W; P3 r; B: B2 k
" f* A/ @- N9 J) d# T