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| DSH 525
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| Applied force for internal parts L( M& G, @; ^: ?% i3 Y6 m
| 13.2: l# j8 h3 a+ Y8 ?
| 60065(ed.6)
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Standard:
+ K+ S$ Y& S( k2 U7 kIEC60065 6ed.$ X5 f4 v6 Q) _" `
Sub clause:* z" W* \6 K& K( m
13.2+ |2 n8 m% y- R# i
Sheet No.5 O/ g' J! w+ b( {- [/ o
525
( }9 C6 c$ g: E5 K% C6 FSubject" T' b( _& f* p
Applied force for internal parts
2 `$ s5 u0 @% IKey words:
4 V2 O0 |) @% D$ g/ n" V5 ?% _4 `force for internal parts
$ L; \0 \& P" c g$ e" j2 [Decision taken at the
1 N9 z$ W" A9 E; X6 y3 v. N40th meeting 2003
+ R& ]3 Y) S8 t0 ]" j0 mQuestion:
0 o2 O# T/ l& Z' e+ _+ `2 K0 wIn clause 13.2, it is specified that 2N for internal parts and 30N for the outside are applied
6 s# _5 K, j5 I$ d7 Asimultaneously while taking measurement of clearance. However, it is not specified that forces are# _$ B0 ~- @ U! _" q
applied to internal parts while taking measurements between two internal parts, ex. primary circuit
2 a, L! b6 P, ]+ ]# lcomponent and secondary circuit component.
9 f8 C3 e# K) B' X8 a, IWhich is the appropriate method to measure clearance between two internal parts ?: M4 x2 w' d: C' d }; ^0 m0 T
a) 2N forces are applied to the both parts simultaneously.( c# c$ u7 S3 d( n. @0 {4 n6 c) \
b) First, a 2N force is applied to one part and removed. And then a 2N is applied to the other one.
# W+ t8 D$ Q* }4 F( M8 Xc) Other opinion9 c3 i- ?, n0 p! }) A9 t4 ?- e5 `
Decision:
6 c6 j# Z; u0 Z3 MFirst, a 2N force is applied to one part and removed. Then a 2N force is applied to the other6 t$ H6 N& ]" T
part.
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