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|  DSH 387% f: g" G- E6 B$ q* ~
( |! D# P2 C' S% C5 u6 d
| Hazardous Voltage& h- U: E3 G5 |. m/ U. Q: y: W
| 1.2.8.3 / 12.8.4: r8 w$ k1 U2 c: ?) r% f" o
| 60950(ed.2) & 60950(ed.3)1 q/ K7 [; R; |" N4 N6 }
|
, l! u# e0 a5 s- m, QStandard:
- |! C" H. i5 ~; _9 D7 S* ~2 p+ |IEC60950, 2nd (3rd) Edition
3 C' \+ p3 a- t& f: V) SSub clause:, P7 o# _1 @$ Y- V/ Q4 w+ a9 S
1.2.8.3(1.2.8.4)6 ^; d& z9 ^" }+ ^" N$ G' \
Sheet n. 387
1 [$ {6 B% H3 x9 F2 l8 Z" jPage 1 (1)
* u9 i' `0 X" l6 zSubject:
P0 L6 W( E" q8 s- N8 A( n- aHazardous Voltage
8 ~- Y: z1 A9 f/ @+ aKey words:/ J6 m4 }$ C1 L( v% N, \2 Q
-Hazardous Voltage
3 K# ^! W' B6 K3 GDecision confirmed
# C) v* C M) J9 j( xat CTL 38th meeting/ D" H: u) _) k. t% E
Question:0 C4 E1 G# y) `0 m
Which of the criteria 42,4Vpeak or 60Vdc do you find should be applied as the compliance7 M$ K. Q& v7 l& s% S. q0 I
criteria, in order to determine whether the voltage shown in the graph is hazardous or not?. |! U/ b0 O. \6 G7 y
Condition: The circuit that generates this voltage is not a limited current circuit.3 O, ^0 ]. g' N: Y- Z) k9 K
Decision:( |3 J& F/ J. d; M* }
This voltage is a hazardous voltage because it exceeds the 42,4Vpeak as written in 1.2.8.31 `9 o' F1 ?( w; y7 R! V1 |2 G
0 {' c X+ J: G4 h1 F" E
f2 V% s! w% R |
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发表于 2012-11-6 17:16
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