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我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头./ x# X. z5 `% H# k) l( {) t
问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:
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/ g3 @8 l( U0 {) _( F# k第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1: U* i s2 T1 i0 ^9 \! j/ D* h+ h- E/ _
20.101.1 Lawn trimmers
! Q$ f7 i$ w: | a' P+ xLawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown
, Q+ X' v" r) |8 z0 Oin Figure 101.. c* r w4 }1 J7 T
The radius X of the guard shall not be smaller than the major swept radius of the cutting
$ s, i8 `' n' [; Q" g6 X- ]6 Thead and the guard shall extend beyond the plane of the cutting element by at least 3 mm2 B. Q: x, x, M) X
for walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall5 E6 w, Q, O2 w8 \4 G
extend at least 45° from the axis of the handle on the side where the cutting element is
7 Z0 u7 r8 ]9 W9 R$ }. o, E- X9 Vmoving away from the operator and at least 90° from the axis of the handle on the side where8 F e+ O- s& k% W& Y5 o# _7 z( ~
the cutting element is moving towards the operator. The vertices of these angles lie on the0 a, o9 p1 K5 r, C8 \
axis of the cutting head spindle.: T% R& J5 c5 h5 V
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)
6 V& X i9 X0 ishall be marked on the lawn trimmer.
& ~0 q+ x0 f8 U& r0 [' x. B+ X4 s! LCompliance is checked by inspection and measurement.0 {; q o- r5 W2 j' m& }5 x+ S
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第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.1039 R# p } N. S! A4 ^5 M- W
22.103 A cutting element shall have a kinetic energy of not more than 10 J.
+ W! _4 D3 {' G) f/ |, ]3 `) B/ DCompliance is checked by inspection, measurement and test. Polyamide cutting elements$ G! ^6 Q9 ]3 j
are stored for at least seven days in a humidity cabinet under the same conditions as those
. F2 \8 r: x' u S1 Irequired for the test of 15.3 before carrying out the test and measurement.
4 b& v* r& {( A3 ~, ^/ TFor the purposes of this standard, the kinetic energy shall be determined by means of the$ E4 {# i$ L# j1 a2 y2 P
following formula:
5 s$ p3 H1 ^& Wkinetic energy = ½ mv2 (J)
6 ^; |9 P7 e5 Owhere. M% L- v6 _9 s) V( j
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);
$ R. [6 ~. ~, G! |v is the maximum attainable velocity of point Z which is half-way along the length L of the9 c- Q$ F3 {3 |" S% o/ o, H
cutting element, in metres per second.' y% V. f" ]* K
Therefore: v = 0,1047 n ( r– (L/2))
, C% u, F1 `% Y! Q2 W. swhere& v" z7 ~1 @' Q$ `9 l
n is the maximum rotational speed with a full length of line or a new cutter fitted, in8 s; O. l; N( y& o
revolutions per minute;; z" l a- [4 T6 p. B- p
r is the distance from the axis of rotation of the cutting head to the outer tip of the cutting' A; a- H+ z6 H! a5 l: i9 F; u4 R# n+ }+ I
means, in metres;
% z2 d" [" M+ k/ ZL is the measured length of the cutting element, in metres.) m1 E$ t6 l4 k. O
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