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[HOUS] DSH 440 Short-circuit of motor capacitors

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发表于 2012-9-14 13:07 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
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DSH 440  y( V' Z6 A# Q6 c' S
! e. o. W  d) q# n  [
Short-circuit of motor capacitors" f8 F, z3 a- s9 a9 o" s. T
19.7, A4 Z# I1 |% N+ a6 y) k
60335-1(ed.3)
- ~$ k% r( G: l  Y! Z' E% O! D

$ J# |  L% j8 C$ j1 A; T9 m: H: qStandard: IEC60335-1:1991, 3rd Ed.7 h% e; d7 [' ~
Sub-clause: 19.7
  g2 _. ?% h( [% @& g7 PSheet No. DSH-440
, N8 y3 T2 q" p1 }" R  j& f0 z4 ISubject: Short-circuit of motor capacitors, @% R: p$ c$ I5 I: h. h+ ~1 b
Key words: -short circuit   -motor capacitor7 Q6 m- {: o& g+ ~5 S
Decision taken at the 40th CTL meeting 2003.0 ~. b& ~6 w/ U
Question:
2 |0 P  a2 u% x2 hTC 61 requested CTL to clarify the test procedure for short-circuiting capacitors in accordance with Sub- }& W0 d9 ^7 x2 E9 [, p* h( v, |
clause 19.7 of IEC 60335-1.5 J# s9 k. V* x# j4 q' `! V
Decision:: _4 s) W" h' h! d+ M) K( z
If the design of the circuit is such that short-circuiting of one capacitor will result in the short-circuiting+ k! Z6 T! D5 W7 I: _
of the second capacitor, only one capacitor needs to be short-circuited. This is endorsed by the sub clause6 K0 Z4 I9 N: c
4.3 that states “If it is evident from the construction of the appliance that a particular test is not- k3 V! `9 M( [# ~% E* ^
applicable, the test is not made”.: z6 m5 B! U5 n/ }
The followings are examples of the circuits.) c' Y, w3 l% q6 |
In the Example A:, L, Q- o0 ~$ z4 G, a
Short-circuit of capacitor (Cb) terminals is necessary according to the requirements. For the1 ~' |4 o( ]5 V- I& ?+ J  q
capacitor (Ca), short-circuit of its terminals when motor is running is not necessary because
. h, a$ b. K, Ithe circuit is opened (the switch is opened).
+ x+ l8 ^9 ^! QAlso short circuit of its terminals (Ca) when the motor starts is not necessary because it is
* H1 d$ s+ g- q. N) j+ W3 D; Talready covered by the short-circuit of Cb terminals.  [+ q7 ?" z& p  F
In the Example B:
  G6 ~, d; a! [- ^) [9 y7 BOnly one short-circuit, either Cb1 or Cb2 terminals, is necessary because the testing of one8 F$ C' u- H/ e$ ^; T
covers the testing of the other one. Also the short-circuit of Ca terminals is not necessary, S- E9 a( n  x* s
because of the reason stated in the Example A." y: t$ O& B( p( v5 X% X

: s" @$ \. A: l  F: F4 ~, F9 r- b7 H- F3 S. d6 N; t
- T9 ]: j3 \$ N* E

6 E! u3 k! J' s- N3 G

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