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小弟最近做到一个灭蚊灯的案子,做的是CE。不太明白60335-2-9中3.1.9的意思,9 u; r- f G p* B- K n7 w5 W" x
normal operation
' r; @7 _- K0 o$ L% V& B5 ~operation of the appliance under the following conditions:
" ~1 _% F8 S i2 p `3 c) M$ f0 f V- C1 j– the output circuit is short-circuited;
3 z8 b- A, B, }& o– the grids are separated by the maximum distance for maintaining an arc, the appliance1 W: b8 n! Z8 B/ i+ [; V0 T
being operated in cycles consisting of 1 s of operation followed by a rest period of 2 s; `, c, E8 l# C5 T4 m0 y8 f
– a resistive load is connected between the grids and adjusted to obtain the maximum$ c% R/ Z- x7 I
current.
8 {. `2 \- p+ x$ |其中对第二点的意思琢磨不透,标准中的意思是把格栅间距加大至可以保持电弧的最大距离,器具循环工作,每个循环包括工作1秒,停2秒,这里想问各位大侠,保持电弧的最大距离怎么确定,器具工作1秒,停2秒又怎么做到。产品如附件。 |
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