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引用第0楼黑土白云于2009-07-01 15:33发表的 故障条件下电源端的剩余电压判断 :
/ [. k6 F: y; `* J, p- @ l1 F$ f4 k60065故障条件下是2S后120V,60950是怎么要求的呢?在哪个条款说的? 8 F- w1 t" `, V7 B. a$ I! x
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根据60950标准2.2.3 Voltages under fault conditions:
) j: F8 v9 y# V3 X* x9 b8 @Except as permitted in 2.3.2.1 b), in the event of a single fault (see 1.4.14), the voltages between
0 F6 K5 W0 G) m5 P4 eany two conductors of the SELV CIRCUIT or CIRCUITS and between any one such conductor and earth 5 E! j. k0 b* l2 j1 F$ G
(see 1.4.9) shall not exceed 42,4 V peak, or 60 V d.c. (V1 in Figure 2E) for longer than 200 ms. * [4 J/ _/ b- I$ N
Moreover, the voltage shall not exceed 71 V peak or 120 V d.c., (V2 in Figure 2E). $ ?8 \1 p3 s& i3 {' B. w* k! I8 G
# A5 H7 W! V2 g6 X7 P
+ o! f* H9 d7 |# s, D0 d/ X就是说60950故障条件下0-200ms之内可是71V peak 或者120V dc。
+ `1 {7 }5 l$ c3 s2 ?8 k200ms之后电压时间内的故障电压不能超过42,4 V peak, or 60 V d.c.。 |
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