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引用第10楼franco于2009-05-07 20:39发表的 :
. \ d* Y. N6 w8 F) O% r- `The oscillating member is moved backwards and forwards through an angle of 90° (45° on
! G+ m8 l% S: W j4 B! i: @$ J0 weither side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
4 t: T% z2 G1 z, F3 S8 x- [# y; ^min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
. L! N5 V6 {& Y1 y; }' T. usample is turned through 90° about the centre line of the cord guard.
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* ]: k6 Z2 \7 m* x+ [. B$ E, U8 C....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。9 o8 z" K# U" a, u" A. x1 F
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翻译成中文的主要意思就是:" [( l8 ]% r7 {7 F
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on 9 v4 W0 \8 H0 g* x6 ]% E* v
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per 5 W9 J$ ~6 M0 C
min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。
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( G2 N+ H+ O: j+ w8 Z这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。
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/ @6 |8 ^5 n" F! RAfter 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。
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这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。( f/ k& g# r, i0 `7 a: C
; f4 ^2 p1 m$ F6 R! a最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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+ e& l0 k+ u# ~8 V: Q+ _7 D这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。& E: y3 r8 Z* \& P: C) z
, P8 W9 A" j% v% R9 X摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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$ e# `- ]) \' X/ Y' r& dA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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