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引用第10楼franco于2009-05-07 20:39发表的 :
( q& Z" Z- \/ _6 m' mThe oscillating member is moved backwards and forwards through an angle of 90° (45° on . _" j! n: q8 ?6 b
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per 4 X n& Q, ~# i7 L$ L
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
m: C$ U1 j" m% E5 p- n7 ^) isample is turned through 90° about the centre line of the cord guard. 8 q9 E" ~- h1 q) x2 R8 b
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....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。* g+ b6 I4 D9 G/ Q
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翻译成中文的主要意思就是: i# A7 l2 O( _6 W. G
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on
/ z/ f7 n$ j1 e0 x2 }- e9 C% S' @either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
1 |0 {3 j- P+ R( C: u7 h* [min. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。( m; P: Q) X$ b. G9 G" z
* N; x1 C+ O: ^! r8 ]这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。3 k3 i x- h0 r" n
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After 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。2 J4 \2 c+ f- C( `4 q D1 f
' }- ^; V* ^/ @这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。& `" W% G3 Z0 q
* s7 m# x/ ?$ V% a) ~这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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; a6 T- n: `8 w# F& S/ {1 t3 q摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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) Z8 C' \# c/ \) Z% YA flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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