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如题,IEC 60601-1 V3.1 版中提到:1 S h" h/ i. S5 l& f) g4 Z: Q
15.4.3.5 * Excessive current and voltage protection3 G2 O$ P) f. [% Y* p' N8 _" u
An INTERNAL ELECTRICAL POWER SOURCE in ME EQUIPMENT shall be provided with an
$ t$ N k- {1 Q, }& B5 i, ?% yappropriately RATED device for protection against fire caused by excessive currents if the
6 |0 \% I8 p: ?' P+ T Ccross-sectional area and layout of the internal wiring or the rating of connected components" x1 _ ^6 m, k( U9 l) p
can give rise to a fire in case of a short circuit. Protective devices shall have adequate
. {4 f. `5 u* d1 c: z# Bbreaking capacity to interrupt the maximum fault current (including short-circuit current) which! ~8 Z& z3 q6 ]; J* ?
can flow. Justification for omission of fuses or OVER-CURRENT RELEASES shall be documented.
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: `" D0 H4 `5 {0 bThe short circuit test between the positive pole and the negative pole of an INTERNAL
2 _* s J- X" g9 J: U# vELECTRICAL POWER SOURCE in the area between the INTERNAL ELECTRICAL POWER SOURCE" y$ N9 _7 f1 V" B* p. y6 B
output contacts and the subsequent protection device may be omitted if two MEANS OF: q) A+ Z* U0 u& S8 L$ {1 V
OPERATOR PROTECTION are provided. Alternatively, a short-circuit test shall not result in any of
* T5 d( F1 h. W1 B2 a, i( _& pthe HAZARDOUS SITUATIONS in 13.1.2.
/ m8 D& G% j9 F, ?9 q7 m对于内部电源设备,如果由于内部线路或连接元件的额定值而可能在短路时导致着火风险,应配有适当额定值的保护装
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置,以防止过电流引起的着火。保护装置应有能够对电路中的最大故障电流(包含短路电流)进行适当切
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z. j6 A+ ]$ [* N断的能力。不采用电流释放器或熔断器的理由应被记录。+ y. G5 @6 i8 B; m
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如果提供了2MOOP,那么在内部电源输出和相应的保护装置之间的区域可以不进行内部电源的正负极短路试验。否则,短路试
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验不应导致13.1.2的任何危险状况。8 n3 b: J/ w5 y5 b( G* s/ Q
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# p( E. s1 }; l* ^2 o+ n6 i重点在第二段,看起来,如果没有做到保护装置+2MOOP,就要做内部电源正负极的短路试验。也有第三方是这么要求的。( q+ t# s. i! [) N2 Y( j
可是我感觉现在小功率的内部电源设备,加保护装置的很少,并且做内部电源短路试验(除非是有保护的锂电池供电)一般都会失败的。
5 m! a1 X, W, h我觉得保护装置是为了降低后续电路短路带来的风险,本身不能减小电池正负极之间的短路的概率及危害,为何要作为电池正负极短路试验的豁免条件呢?应该是后续电路的短路故障态测试的豁免条件才对呢。3 O( q* D4 z! M7 ]+ H' F$ w; Q
请问各位大虾,大家有没有碰到这种情况,大家是怎么理解的?
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