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标题: 电动打草机线头飞溅伤脚问题 [打印本页]

作者: terrywong    时间: 2014-3-15 18:44
标题: 电动打草机线头飞溅伤脚问题
我们一款打草机,在国外遭投诉, 原因是打草线自动切断后,线头飞出,打疼用户的脚趾头.
" f8 J/ K) j9 D9 F9 @* V问题产品在国外, 看不到, 我觉得原因是如下两点, 请各位帮忙分析对不对:( k) ^, W: s5 \' P- C

$ a* p# ~) c2 N* k' x6 V第一, 护罩尺寸及角度不对, 参见IEC 60335-2-91, 20.101.1
  |2 g/ v# D3 P( w% b9 H5 _20.101.1 Lawn trimmers' [2 u3 \- O; q1 ^
Lawn trimmers shall be guarded on the operator’s side, as a minimum, to the extent shown
+ b2 {2 B. |& B2 x. C* ~in Figure 101.( ~! o' s2 ?- R1 B; m4 u
The radius X of the guard shall not be smaller than the major swept radius of the cutting1 o9 P" b3 @3 q
head and the guard shall extend beyond the plane of the cutting element by at least 3 mm
3 `3 f8 k* H" x' k$ W! yfor walk-behind lawn trimmers and 10 mm for hand-held lawn trimmers. The guard shall
1 g9 g' A1 z( Z. q. {6 q/ k  |extend at least 45° from the axis of the handle on the side where the cutting element is
1 e3 \1 ]6 i7 `moving away from the operator and at least 90° from the axis of the handle on the side where
; \' T) ^7 d* S/ Mthe cutting element is moving towards the operator. The vertices of these angles lie on the
0 k% t0 E9 x4 j+ Y4 laxis of the cutting head spindle.1 V( {% d( K/ R( ^
If the guarding is less than a total of 360°, the direction of rotation of the cutting element(s)
9 o+ ?! J- V1 ~shall be marked on the lawn trimmer.
- P% T$ Z# ~9 a/ v0 {4 d0 yCompliance is checked by inspection and measurement.
* N3 N( {2 S1 Z$ J0 C, r& S- I& `" Z. Q' {. L
第二, 飞出线头动能太大. 参见 IEC 60335-2-91, 22.103- V! \" m* a" ], f# |& `
22.103 A cutting element shall have a kinetic energy of not more than 10 J.( A' L- Q5 s$ U3 p6 Y7 N
Compliance is checked by inspection, measurement and test. Polyamide cutting elements
& `* A5 n3 I9 y2 E3 Y& R6 x7 ^! Xare stored for at least seven days in a humidity cabinet under the same conditions as those
! E: w1 R& R: I* M$ {required for the test of 15.3 before carrying out the test and measurement.! `8 p6 Y; Z8 i4 m
For the purposes of this standard, the kinetic energy shall be determined by means of the6 e( |/ V# \5 x" L/ u1 o" u: u
following formula:# w% d: Y9 T) W3 V
kinetic energy = ½ mv2 (J)
/ G# M/ d5 u7 l2 b0 Kwhere3 V4 t4 l' J) }4 q; R- U5 |
m is the mass of the length L of the cutting element, in kilograms (see Figure 105);
9 u- ]6 ]+ b  e& ^' m+ d7 Kv is the maximum attainable velocity of point Z which is half-way along the length L of the% W; V8 r9 r3 P1 }) T0 f. U( M
cutting element, in metres per second.) c% X, X: n% y7 ?9 C
Therefore: v = 0,1047 n ( r– (L/2))* q2 C2 ~8 \8 w) z- [
where
  p/ [% {; r* C) c6 s  \, G: b. S- yn is the maximum rotational speed with a full length of line or a new cutter fitted, in
& |+ t+ T3 e, \" brevolutions per minute;
" s$ y% E; w2 Z: Qr is the distance from the axis of rotation of the cutting head to the outer tip of the cutting3 {5 c# w  O# D& _$ w
means, in metres;
/ y) c# w" X/ I( ~2 p6 ?L is the measured length of the cutting element, in metres.
! @7 k8 j; F. p, [, c; s. z! u) L
2 q9 }2 k/ {5 v1 \. {! T' Z! I7 C. j; B; n/ q, ], h" S

作者: noangelrain    时间: 2014-3-19 19:23
关键你们认证的这不满足 ,是如何拿到证书的
作者: terrywong    时间: 2014-3-21 15:54
CE-LVD/MD 测试都通过, 也拿到了某机构的GS证书.  但还是有投诉, 证书的严肃性我们暂且不谈, 只想单纯谈论问题, 和解决问题的方法. 不知道我的上述分析对不对, 如果对, 可否告知解决方案, 请各位不吝指教. 谢谢啦
作者: lianhuatang    时间: 2014-3-24 14:07
认证的产品也不能肯定解决实际使用中的可能遭遇。% w, ]" C9 ]6 L. [# q
确定是纯的尼龙线吧?直径应该在2.3mm以内吧?
作者: kongyezi    时间: 2014-4-19 16:28
是的可能的,护罩导向问题,以及客户如何操作是否手持方向不对??
作者: zjfxw    时间: 2014-8-26 10:07
这种现象偶然比较大吧,
作者: kgdihcel123    时间: 2014-9-25 10:55
没看到贵司产品的护罩图片,也不能给出准确的信息:
- m2 J3 i% K% ^. i  B1 _6 ^5 g3 L- n- b1.防护罩是否存在变形,防护角度是否符合要求,4.6.2(附录2a、2b) 4.6.3(附录 3a、3b),因为护罩变形了,它的底部防护就有可能不密实,尼龙线会飞出来的。1 _* a0 Z+ X, p, y" g
2.客户操作的方向是否正确




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